JEE Advanced Physics: Trigonometric Functions questions with solutions

Q1. Find the value of sin(480 deg). [Note: this is a trigonometry problem misclassified under Physics.]

1. 1/2
2. 1
3. sqrt(3)/2
4. -sqrt(3)/2

Answer: sqrt(3)/2

sin(480 deg) = sin(480 - 360 deg) = sin(120 deg). Since 120 deg is in the second quadrant: sin(120 deg) = sin(180 deg - 60 deg) = sin(60 deg) = sqrt(3)/2.

Q2. What is the value of sin(15 deg) * cos(15 deg)?

1. 1/2
2. 1/3
3. 1/4
4. 1/12

Answer: 1/4

By the double-angle formula, sin(15)*cos(15) = (1/2)*sin(30) = (1/2)*(1/2) = 1/4.