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ExamsJEE AdvancedPhysics

Find the value of sin(480 deg). [Note: this is a trigonometry problem misclassified under Physics.]

  1. 1/2
  2. 1
  3. sqrt(3)/2
  4. -sqrt(3)/2

Correct answer: sqrt(3)/2

Solution

sin(480 deg) = sin(480 - 360 deg) = sin(120 deg). Since 120 deg is in the second quadrant: sin(120 deg) = sin(180 deg - 60 deg) = sin(60 deg) = sqrt(3)/2.

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