Exams › JEE Advanced › Physics
A plane wavefront AB travelling in air strikes a flat glass surface XY, and CD is the corresponding refracted wavefront. The refractive index of glass relative to air equals:
- BD/AC
- AB/CD
- BD/AD
- AC/AD
Correct answer: BD/AC
Solution
Using Huygens' construction, while the wavelet from B travels distance BD in air, the wavelet from A travels AC in glass in the same time. Since n = c_air/c_glass = (distance in air)/(distance in glass) for the same time, n = BD/AC.
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →