Exams › JEE Advanced › Physics
Two coherent point sources separated by a distance d = 5 micrometers emit light of wavelength lambda = 2 micrometers in phase. A circular wire of radius R = 20 micrometers is placed symmetrically around the two sources (sources lie along a diameter). Points A and B are at the ends of the diameter along the line joining the sources; points C and D are at the ends of the diameter perpendicular to the line joining the sources. Which of the following is correct?
- (A) Points A and B are dark and points C and D are bright.
- (B) Points A and B are bright and points C and D are dark.
- (C) Points A and C are dark and points B and D are bright.
- (D) Points A and C are bright and points B and D are dark.
Correct answer: (B) Points A and B are bright and points C and D are dark.
Solution
For two coherent sources separated by d = 5 um, wavelength lambda = 2 um. Path difference at angle theta from the source axis = d*cos(theta). At A (theta = 0): PD = 5 um = 2.5*lambda -> destructive (dark). At B (theta = 180): PD = 5*cos(180) = -5 um, |PD| = 2.5*lambda -> dark. At C or D (theta = 90): PD = 0 -> constructive (bright). So A and B are dark; C and D are bright.
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →