Exams › JEE Advanced › Physics
Correct answer: The fringe width changes in inverse proportion
Fringe width beta = lambda*D/d, so with lambda and D fixed, beta is inversely proportional to d (option B correct). Angular fringe width = lambda/d, which depends on d, so it does change (option A wrong). The position of the n-th bright fringe is yₙ = n*lambda*D/d and the n-th dark fringe is y = (n+1/2)*lambda*D/d; both depend on d, so the positions of maxima and minima change as d changes (options C and D are also physically correct). The single best/primary answer that captures the quantitative behavior is that the fringe width changes in inverse proportion to d.