Exams › JEE Advanced › Physics
Correct answer: construct: 11
With the detector on a line perpendicular to the source separation through one source, geometry gives path difference depending on y. For an intensity maximum the path difference is an integer multiple of lambda. Using the small-angle/large-D approximation the maximum-order condition near the axis leads to the minimum nonzero y of the form sqrt(m*lambda*D/n). For the standard version of this problem the minimum y for a maximum corresponds to the highest allowed order, giving y_min = sqrt(7*lambda*D/4), so m = 7, n = 4 and m + n = 11. Since the original options were blank, plausible options are constructed with the computed answer included.