StreakPeaked· Practice

ExamsJEE AdvancedPhysics

A rod of length L and uniform cross-section has a thermal conductivity that varies linearly from 2K at end A to K at end B. End A is held at 100 degC and end B at 0 degC. In the steady state, which best describes the temperature profile T(x), where x is the distance measured from end A?

  1. A curve that falls from 100 degC to 0 degC, steeper near end B than near end A (concave, of logarithmic shape)
  2. A straight line falling uniformly from 100 degC to 0 degC
  3. A curve that falls steeper near end A than near end B (concave the other way)
  4. A curve that first rises above 100 degC and then falls to 0 degC

Correct answer: A curve that falls from 100 degC to 0 degC, steeper near end B than near end A (concave, of logarithmic shape)

Solution

Write k(x) = 2K - (K/L)x = K(2 - x/L), which is largest at A and smallest at B. In steady state the heat current Q is constant along the rod, so dT/dx = -Q/(A*k(x)). Since k is large near A, |dT/dx| is small there (gentle slope); since k is small near B, |dT/dx| is large there (steep slope). The temperature therefore drops slowly at first and rapidly near B, giving a concave (logarithmic-type) curve from 100 degC to 0 degC, not a straight line.

Related JEE Advanced Physics questions

⚔️ Practice JEE Advanced Physics free + battle 1v1 →