StreakPeaked· Practice

ExamsJEE AdvancedPhysics

A composite wall is built from two layers A and B of equal thickness but made of different materials. The thermal conductivity of layer A is three times that of layer B. In steady-state conditions, the total temperature difference across the entire wall is 36 deg C. What is the temperature difference across layer A alone?

  1. 6 deg C
  2. 9 deg C
  3. 18 deg C
  4. 27 deg C

Correct answer: 9 deg C

Solution

Equal heat flux through both layers gives k_A * dT_A = k_B * dT_B. With k_A = 3k_B this means dT_B = 3 * dT_A. Combined with dT_A + dT_B = 36 deg C, we get 4 * dT_A = 36, so dT_A = 9 deg C.

Related JEE Advanced Physics questions

⚔️ Practice JEE Advanced Physics free + battle 1v1 →