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ExamsJEE AdvancedPhysics

50 g of ice at -10 deg C is mixed with 20 g of steam at 100 deg C inside a calorimeter of water equivalent 1.5 g (initially at 0 deg C). After the mixture reaches steady state, which statement is correct? (Latent heat of vaporization = 540 cal/g, latent heat of fusion = 80 cal/g, specific heat of water = 1 cal/g/deg C, specific heat of ice = 0.5 cal/g/deg C.)

  1. Mass of water remaining is 67.4 g
  2. Mass of steam remaining is 2.6 g
  3. Mass of water remaining is 67.87 g
  4. Mass of steam remaining is 2.13 g

Correct answer: Mass of water remaining is 67.4 g

Solution

Heating ice (and calorimeter) up to 100 deg C needs 9400 cal, condensing 9400/540 = 17.4 g of steam; the remaining water is the 50 g (melted ice) plus 17.4 g condensed = about 67.4 g, with about 2.6 g of steam left.

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