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ExamsJEE AdvancedPhysics

A rod enclosed in a thermally insulating sheath has its two ends maintained at temperatures T1 and T2. It is made of two joined sections of lengths l1 and l2 with thermal conductivities x1 and x2 respectively (the T1 end is the l1 section). In steady state, find the temperature at the junction (interface) of the two sections.

  1. (x1*l2*T1 + x2*l1*T2)/(x1*l2 + x2*l1)
  2. (x1*l1*T1 + x2*l2*T2)/(x1*l1 + x2*l2)
  3. (x1*T1 + x2*T2)/(x1 + x2)
  4. (l1*T1 + l2*T2)/(l1 + l2)

Correct answer: (x1*l2*T1 + x2*l1*T2)/(x1*l2 + x2*l1)

Solution

Equating the steady-state heat current through the two series sections and solving for the junction temperature T gives T = (x1*l2*T1 + x2*l1*T2)/(x1*l2 + x2*l1).

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