StreakPeaked· Practice

ExamsJEE AdvancedPhysics

A thermally insulated vessel holds water at 0 deg C. It is connected to a vacuum pump that removes water vapour, and the energy for vaporization causes part of the remaining water to freeze. Given latent heat of vaporization at 0 deg C = 21 x 10⁵ J/kg and latent heat of fusion = 3.36 x 10⁵ J/kg, find the maximum percentage of the water that can be frozen.

  1. 86.2%
  2. 33.6%
  3. 21%
  4. 24.36%

Correct answer: 86.2%

Solution

Energy balance m_v*L_vap = m_f*L_fus together with m_v + m_f = M gives the frozen fraction m_f/M = L_vap/(L_vap + L_fus) = about 86.2%.

Related JEE Advanced Physics questions

⚔️ Practice JEE Advanced Physics free + battle 1v1 →