StreakPeaked· Practice

ExamsJEE AdvancedPhysics

Steam keeps the inner surface of a 50 cm long rubber tube at 120°C; the tube has inner radius 1.0 cm and outer radius 1.2 cm. The room is at 30°C. Taking the thermal conductivity of rubber as 0.15 J/m-s-°C, find the rate of radial heat conduction through the tube wall.

  1. 183 J/s
  2. 207 J/s
  3. 233 J/s
  4. 280 J/s

Correct answer: 233 J/s

Solution

Using the cylindrical-shell conduction formula with ln(1.2) ≈ 0.182 gives about 233 J/s.

Related JEE Advanced Physics questions

⚔️ Practice JEE Advanced Physics free + battle 1v1 →