StreakPeaked· Practice

ExamsJEE AdvancedPhysics

A steel rod (Young's modulus Y = 2.0 * 10¹¹ N/m², linear expansion coefficient alpha = 10⁻⁵ per deg C) of length 4 m and cross-sectional area 10 cm² is heated from 0 deg C to 400 deg C while its ends are clamped so it cannot expand. The tension produced is x * 10⁵ N. Find x.

  1. 4
  2. 6
  3. 8
  4. 10

Correct answer: 8

Solution

Thermal tension F = Y*alpha*dT*A = 2.0*10¹¹ * 10⁻⁵ * 400 * 10*10⁻⁴ = 8*10⁵ N, so x = 8.

Related JEE Advanced Physics questions

⚔️ Practice JEE Advanced Physics free + battle 1v1 →