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For which of the following orbitals is the number of radial nodes equal to the number of angular nodes?
- 3p
- 4d
- 5d
- 6f
Correct answer: 3p
Solution
Setting radial nodes = angular nodes: n - l - 1 = l -> n = 2l + 1. For 3p (n=3, l=1): n = 2(1)+1 = 3. Satisfied. For 5d (n=5, l=2): n = 2(2)+1 = 5. Also satisfied. The simplest orbital satisfying this condition among the options is 3p.
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