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What is the correct set of four quantum numbers (n, l, ml, ms) for the valence electron of the rubidium atom (Z = 37)?
- 5, 1, 1, +1/2
- 5, 0, 1, +1/2
- 5, 0, 0, +1/2
- 5, 1, 0, +1/2
Correct answer: 5, 0, 0, +1/2
Solution
Rubidium has configuration [Kr]5s¹. The single valence electron is in the 5s orbital: n=5, l=0, ml=0, ms=+1/2.
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