Exams › JEE Advanced › Physics
A graph shows the average power absorbed (P_av) by a driven oscillator plotted against the driving frequency. Consider the following statements: (1) The sharpness of the resonance peak is determined by the damping constant. (2) The sharpness of resonance is defined by the ratio (omega2 - omega1) / omega0, where omega1 and omega2 are the half-power frequencies and omega0 is the resonant frequency. (3) Maximum power is absorbed at the frequency of velocity resonance. Which statements are correct?
- (A) (1) and (2)
- (B) (2) and (3)
- (C) (1) and (3)
- (D) (1), (2) and (3)
Correct answer: (C) (1) and (3)
Solution
At velocity resonance (omega = omega0), impedance is minimum (purely resistive), so current/velocity amplitude is maximum and power absorbed is maximum. The Q-factor = omega0/(omega2 - omega1), so statement (2) has the ratio inverted and is false.
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →