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A particle constrained to move along the x-axis has a potential energy described by U(x) = k[1 - exp(-x²)], where k is a positive constant and -∞ ≤ x ≤ +∞. Which of the following statements is true?
- The particle is in an unstable equilibrium at positions away from the origin.
- For any finite, nonzero x, the force on the particle points outward from the origin.
- If the total mechanical energy is k/2, the particle's kinetic energy is least at the origin.
- The motion near x = 0 is simple harmonic for small displacements.
Correct answer: The motion near x = 0 is simple harmonic for small displacements.
Solution
U(x)=k[1-exp(-x^2)] has U'(x)=2kx*exp(-x^2), giving a stable minimum at x=0 where U=0. For small x, U approximately k*x^2, so the motion is simple harmonic. The stored claim that KE is least at the origin is false (KE is maximum there since U is minimum).
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