Exams › JEE Advanced › Physics
The root mean square speed of an unknown gas at 727 deg C is 10⁵ cm/s. Calculate the molar mass of the gas in g/mol. (Given: R = 25/3 J/(mol K))
- 25
- 50
- 75
- 100
Correct answer: 25
Solution
Substituting v_rms = 1000 m/s and T = 1000 K into v_rms² = 3RT/M gives M = 3*(25/3)*1000/10⁶ = 0.025 kg/mol = 25 g/mol.
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →