The average kinetic energy of a single atom is calculated as (3/2)kT, where k = 1.38 × 10⁻²³ J/K and T = 160 K. What is the resulting value?

3.312 × 10⁻²¹ J
3.412 × 10⁻²¹ J
3.212 × 10⁻²¹ J
3.512 × 10⁻²¹ J

Correct answer: 3.312 × 10⁻²¹ J

Solution

Average KE = (3/2)kT = 1.5 x 1.38e-23 x 160 = 3.312e-21 J, which is option index 0. The stored answer 3.212e-21 J (index 2) is an arithmetic error.

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