Exams › JEE Advanced › Physics
An experimentalist uses a Michelson interferometer to measure a wavelength of light emitted by neon atoms. She slowly moves mirror M2 until 10000 new bright central fringes have appeared. She then measures that the mirror has moved a distance of 3.164 mm. What is the wavelength of the light (in nm)?
- 316.4
- 632.8
- 158.2
- 1265.6
Correct answer: 632.8
Solution
When mirror M2 moves by d = 3.164 mm, the optical path difference changes by 2d. For N = 10000 fringes: lambda = 2d/N = 2 * 3.164 mm / 10000 = 6.328e-4 mm = 632.8 nm.
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →