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ExamsJEE AdvancedPhysics

A conducting solid sphere of radius R carries a uniform total charge Q and rotates with angular velocity omega about its axis. A uniform external magnetic field B is applied perpendicular to the axis of rotation. Find the torque experienced by the sphere.

  1. Q*omega*R²*B / 5
  2. Q*omega*R²*B / 3
  3. Q*omega*R²*B / 4
  4. Q*omega*R²*B / 2

Correct answer: Q*omega*R²*B / 5

Solution

A rotating charged solid sphere with uniform volume charge density rho = Q / (4/3 * pi * R³). Consider a thin shell at radius r with thickness dr: charge dq = rho * 4*pi*r² * dr. This shell rotates with omega, acting as a current loop. Magnetic moment of shell: dM = (1/3)*dq*omega*r² (for a spherical shell, dM = dq*omega*r²/3... actually for a ring at colatitude theta: dM contribution). For a uniformly charged solid sphere: M_total = Q*omega*R²/5. Torque = M * B = Q*omega*R²*B/5.

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