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ExamsJEE AdvancedPhysics

A particle of charge 20 μC and mass 20 μg moves in a circular orbit of radius 5 cm under the influence of a uniform magnetic field B = 0.1 T. At point P on the circle, a uniform electric field is suddenly switched on, after which the particle moves along the tangent at P with constant velocity. What is the magnitude of the electric field?

  1. 2 V/m
  2. 1 V/m
  3. 0.5 V/m
  4. 5 V/m

Correct answer: 0.5 V/m

Solution

The orbital speed is v = qBr/m = 5 m/s. When the particle moves tangentially at constant speed, the net force is zero; the electric force qE must exactly cancel the centripetal magnetic force qvB, giving E = vB = 5 * 0.1 = 0.5 V/m.

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