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ExamsJEE AdvancedPhysics

An object of mass 2 kg has a specific heat of 5 cal/(kg·°F). An electric heater rated at 4200 J/s converts 20% of its electrical energy into heat and is used to heat the object for 10 s. If the resulting temperature rise is expressed as (100/n) °C, find the integer n.

  1. 1
  2. 2
  3. 3
  4. 4

Correct answer: 1

Solution

Converting c = 5 cal/(kg·°F) gives 5 * 4.2 * (9/5) = 37.8 J/(kg·°C). Heat delivered = 4200 * 0.20 * 10 = 8400 J. ΔT = 8400/(2 * 37.8) ≈ 111°C ≈ 100/1, so n = 1.

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