StreakPeaked· Practice

ExamsJEE AdvancedPhysics

A sealed vessel of volume V initially contains gas at pressure P0. Gas is evacuated isothermally at a constant volumetric rate C (volume measured at instantaneous pressure). Which of the following options are correct?

  1. Pressure P at time t is P0 * e^(-C*t/V)
  2. Pressure P at time t is P0 - C*t/V
  3. Number of moles evacuated in time t is linearly proportional to t
  4. Number of moles evacuated in time t is exponentially dependent on t

Correct answer: Pressure P at time t is P0 * e^(-C*t/V)

Solution

Since the vessel volume V is fixed and process is isothermal, n proportional to P. Rate of moles removed = C*P/(RT) (rate of volume removed * density at current pressure). moles in vessel n = PV/(RT). dn/dt = V/(RT) * dP/dt = -C*P/(RT). So dP/dt = -CP/V. Solution: P = P0*e^(-Ct/V). Moles evacuated = integral of C*P/(RT) dt = C*P0/(RT) * integral e^(-Ct/V) dt = (P0*V/RT)*(1 - e^(-Ct/V)). This is exponential in t, not linear. So options 1 and 4 are correct.

Related JEE Advanced Physics questions

⚔️ Practice JEE Advanced Physics free + battle 1v1 →