Exams › JEE Advanced › Physics
Correct answer: Pressure P at time t is P0 * e^(-C*t/V)
Since the vessel volume V is fixed and process is isothermal, n proportional to P. Rate of moles removed = C*P/(RT) (rate of volume removed * density at current pressure). moles in vessel n = PV/(RT). dn/dt = V/(RT) * dP/dt = -C*P/(RT). So dP/dt = -CP/V. Solution: P = P0*e^(-Ct/V). Moles evacuated = integral of C*P/(RT) dt = C*P0/(RT) * integral e^(-Ct/V) dt = (P0*V/RT)*(1 - e^(-Ct/V)). This is exponential in t, not linear. So options 1 and 4 are correct.