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For an ideal gas at a fixed pressure, the mean free path is

1. Independent of temperature
2. Decreases as temperature rises
3. Increases as temperature rises
4. Directly proportional to T²

Correct answer: Increases as temperature rises

Solution

Mean free path lambda = kT / (sqrt(2) * pi * d² * P). At constant pressure, lambda is directly proportional to T, so it increases as temperature rises.

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