StreakPeaked· Practice

ExamsJEE AdvancedPhysics

Find the ratio of the root-mean-square (rms) speed of H2 at 50 K to the rms speed of O2 at 800 K.

  1. 1
  2. 2
  3. 4
  4. 8

Correct answer: 1

Solution

v_rms = sqrt(3RT/M). Ratio = sqrt[(T_H2 / M_H2) / (T_O2 / M_O2)] = sqrt[(50/2) / (800/32)] = sqrt[25 / 25] = sqrt(1) = 1.

Related JEE Advanced Physics questions

⚔️ Practice JEE Advanced Physics free + battle 1v1 →