Exams › JEE Advanced › Physics
Correct answer: 1 and 3
The point P is directly in front of one slit, at a lateral distance of b/2 from the midpoint (central axis). Path difference at P: delta = b*(b/2)/d = b²/(2d). A wavelength is missing (dark fringe / destructive interference) when delta = (2n+1)*lambda/2 for integer n >= 0. So lambda = 2*delta/(2n+1) = b²/((2n+1)*d). For n=0: lambda = b²/d (option 1). For n=1: lambda = b²/(3d) (option 3). Options 2 and 4 correspond to bright fringe conditions. Missing wavelengths: 1 and 3.