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ExamsJEE AdvancedPhysics

A copper rod and a steel rod, each of equal length and equal cross-sectional area, are joined end to end. The free end of the copper rod is maintained at 0 degree C and the free end of the steel rod is maintained at 100 degree C. Find the temperature at the junction. (Thermal conductivity of copper = 390 W/(m*deg C) and of steel = 46 W/(m*deg C).)

  1. 5.3 deg C
  2. 10.6 deg C
  3. 20.1 deg C
  4. 15 deg C

Correct answer: 10.6 deg C

Solution

At steady state, the heat current is the same in both rods. Let T be the junction temperature. For copper (0 deg C end): Q/t = K_Cu * A * (T - 0) / L = 390 * A * T / L. For steel (100 deg C end): Q/t = K_St * A * (100 - T) / L = 46 * A * (100 - T) / L. Setting equal: 390T = 46(100 - T) = 4600 - 46T. 390T + 46T = 4600. 436T = 4600. T = 4600/436 = 10.55 deg C, approximately 10.6 deg C.

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