Exams › JEE Advanced › Physics
Correct answer: 28
For an ideal gas: v_rms = sqrt(3RT/M) and v_avg = sqrt(8RT/(pi*M)). Their ratio: v_rms/v_avg = sqrt(3*pi/8). Given ratio = sqrt((alpha+5)/alpha). Equating: (alpha+5)/alpha = 3*pi/8. With pi = 22/7: 3*(22/7)/8 = 66/56 = 33/28. So (alpha+5)/alpha = 33/28 → 28*(alpha+5) = 33*alpha → 28*alpha + 140 = 33*alpha → 5*alpha = 140 → alpha = 28.