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ExamsJEE AdvancedPhysics

A solid sphere and a cube of the same material and the same volume are heated to the same temperature and allowed to cool under identical surroundings. What is the ratio of the total thermal radiation emitted by the sphere to that emitted by the cube?

  1. 1: 1
  2. 4*pi/3: 1
  3. (pi/6)^(1/3): 1
  4. (1/2)*(4*pi/3)^(2/3): 1

Correct answer: (pi/6)^(1/3): 1

Solution

Same volume V. Sphere: V = (4/3)*pi*r³ -> r = (3V/(4*pi))^(1/3). Surface area of sphere: Aₛ = 4*pi*r² = 4*pi*(3V/(4*pi))^(2/3). Cube: V = a³ -> a = V^(1/3). Surface area of cube: A_c = 6*a² = 6*V^(2/3). Ratio Aₛ/A_c = 4*pi*(3V/(4*pi))^(2/3) / (6*V^(2/3)) = (4*pi/6) * (3/(4*pi))^(2/3) = (2*pi/3)*(3/(4*pi))^(2/3). Simplifying: (2*pi/3) * 3^(2/3) / (4*pi)^(2/3) = (2*pi/3) * 3^(2/3) / (4^(2/3)*pi^(2/3)) = 2*pi^(1/3)*3^(2/3-1) / (4^(2/3)) =... This simplifies to (pi/6)^(1/3). Since radiation rate is proportional to surface area, ratio is (pi/6)^(1/3): 1.

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