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ExamsJEE AdvancedPhysics

A clock fitted with a metallic pendulum gains 5 s per day at 15 degrees C and loses 10 s per day at 33 degrees C. What is the coefficient of linear expansion of the metal (express your answer as the nearest value in units of 10⁻⁵ per degree C)?

  1. 1.2 * 10⁻⁵ /deg C
  2. 1.9 * 10⁻⁵ /deg C
  3. 2.4 * 10⁻⁵ /deg C
  4. 3.2 * 10⁻⁵ /deg C

Correct answer: 1.9 * 10⁻⁵ /deg C

Solution

The pendulum period Tₚ = 2*pi*sqrt(L/g). When temperature changes by delta_T, L changes by alpha*delta_T*L, so Tₚ changes by (1/2)*alpha*delta_T*Tₚ. The fractional change in time kept per day equals (1/2)*alpha*delta_T. Using the two given conditions one can find both the calibration temperature T0 and alpha.

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