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ExamsJEE AdvancedPhysics

A metal rod is heated by a wire that delivers constant power $P$. The rod is placed inside an insulated container, and its temperature $T$ varies with time $t$ as $T(t)=T_0(1+\beta t^4)$, where $\beta$ is a constant with suitable dimensions and $T_0$ is a constant representing temperature. What is the heat capacity of the metal rod?

  1. $\dfrac{4P\big(T(t)-T_0\big)^3}{\beta T_0^4}$
  2. $\dfrac{4P\big(T(t)-T_0\big)}{\beta T_0^4}$
  3. $\dfrac{4P\big(T(t)-T_0\big)^4}{\beta T_0^3}$
  4. $\dfrac{4P\big(T(t)-T_0\big)^2}{\beta T_0^3}$

Correct answer: $\dfrac{4P\big(T(t)-T_0\big)^2}{\beta T_0^3}$

Solution

For an insulated rod receiving constant power, the rate of heat gain is $P=C\,dT/dt$, where $C$ is the heat capacity. Differentiating the given temperature law and eliminating $t$ in favor of $T-T_0$ gives the required dependence. The resulting expression matches option D.

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