Exams › JEE Advanced › Maths
If the fourth root of (the cube root of x²) equals x^k, find k.
- 2/6
- 6
- 1/6
- 7
Correct answer: 1/6
Solution
The cube root of x² is x^(2/3); its fourth root is x^((2/3)/4) = x^(2/12) = x^(1/6). So k = 1/6.
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