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In a trapezium ABCD with AB parallel to DC, E and F are the midpoints of the two diagonals. Given DC = 60 and EF = 5, find the length of AB.
- 40
- 45
- 50
- 55
Correct answer: 50
Solution
In a trapezium, the line segment joining the midpoints of the diagonals is parallel to the two bases and its length equals half the difference of the parallel sides: EF = |DC - AB|/2. So 5 = (60 - AB)/2, giving 60 - AB = 10, hence AB = 50.
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