Exams › JEE Advanced › Maths
How many rational terms are present in the expansion of (1 + sqrt(2) + sqrt(5))⁶?
- 7
- 10
- 6
- 8
Correct answer: 10
Solution
In the multinomial expansion (1 + sqrt(2) + sqrt(5))⁶ = sum [6!/(a!b!c!)] * 1^a * (sqrt(2))^b * (sqrt(5))^c with a+b+c=6, a term is rational iff b and c are both even; the valid (b,c) pairs are (0,0),(0,2),(0,4),(0,6),(2,0),(2,2),(2,4),(4,0),(4,2),(6,0) — exactly 10 pairs.
Related JEE Advanced Maths questions
- In the expansion of (1 + x)ⁿ, let the binomial coefficients be represented as C₀, C₁, C₂,..., Cₙ. If p and q are such that p + q = 1, what is the value of Σᵣ₌₀ nCr pʳqⁿ⁻ʳ?
- What is the result of the summation Σ₀≤k≤n ∑ᵢ i * Cᵢ?
- The expression E5(n) is defined as Σ (nCk × k⁴) / Σ (nCk × k³), and it simplifies to n / 4. For n ≤ 109, E5(n) is less than 26. Therefore, the smallest value of n that satisfies the condition E5(n) ≥ 26 is one of the following:
- What is the coefficient of x¹¹ in the expansion of (1 + x²)⁴ (1 + x³)⁷ (1 + x)¹²?
- What is the coefficient of x⁵⁰ in the expansion of the sum S = sum(r=0 to 100) [ C(100,r) * (x-3)^(100-r) * 2^r ]?
- Evaluate the sum T = sum(r=0 to 20) r*(20-r)*[C(20,r)]².
⚔️ Practice JEE Advanced Maths free + battle 1v1 →