Exams › JEE Advanced › Maths
The ratio of the area of a regular n-sided polygon circumscribed about a circle to the area of the regular n-sided polygon inscribed in the same circle is 4:3. Find the value of n.
- 3
- 6
- 9
- 10
Correct answer: 6
Solution
A_circ / A_ins = [n*r²*tan(pi/n)] / [n*r²*sin(pi/n)*cos(pi/n)] = tan(pi/n) / (sin(pi/n)*cos(pi/n)) = 1/cos²(pi/n). Setting 1/cos²(pi/n) = 4/3 gives cos²(pi/n) = 3/4, so cos(pi/n) = sqrt(3)/2, meaning pi/n = pi/6, so n = 6.
Related JEE Advanced Maths questions
- For a natural number n, the polynomial fₙ(x) of degree n is defined by fₙ(cos(theta)) = cos(n*theta). Given f₂(x) = 2x² - 1 and f₃(x) = 4x³ - 3x, if f₆(x) = p*x⁶ + q*x⁴ + r*x² + s, find the value of 7*(p + q + r - s).
- Let x and y be real numbers such that sin(x)/sin(y) = 3 and cos(x)/cos(y) = 1/2. The value of sin(2x)/sin(2y) + cos(2x)/cos(2y) can be written as p/q where p and q are coprime positive integers. Find p + q.
- In a chemistry class, there are 20 students, while a physics class has 30 students. If 10 students are enrolled in both classes, and the two classes are held at separate times, determine the value of k/8, where k represents the total number of students attending either class.
- Given that A represents the divisors of 15, B contains prime numbers less than 10, and C includes even numbers less than 9, how many elements are there in the intersection of (A ∪ C) and B?
- Identify the periodic function among the following:
- The function f(x) = √|x² - 5| x + 6 + √8 + 2|x| - |x|² is defined as a real number for values of x within which range?
⚔️ Practice JEE Advanced Maths free + battle 1v1 →