Exams › JEE Advanced › Maths
Let A be the 2x2 matrix with first row (0, 1) and second row (0, 0), and let I be the 2x2 identity matrix. If (I + A)²⁰ - 19A = [[alpha, beta], [gamma, delta]], find alpha + beta + gamma + delta.
- 0
- 1
- 2
- 3
Correct answer: 3
Solution
Since A² = 0, by the binomial theorem (I+A)²⁰ = I + 20A. Then (I+A)²⁰ - 19A = I + 20A - 19A = I + A = [[1,1],[0,1]]. Sum of entries: 1 + 1 + 0 + 1 = 3.
Related JEE Advanced Maths questions
- In the expansion of (1 + x)ⁿ, let the binomial coefficients be represented as C₀, C₁, C₂,..., Cₙ. If p and q are such that p + q = 1, what is the value of Σᵣ₌₀ nCr pʳqⁿ⁻ʳ?
- What is the result of the summation Σ₀≤k≤n ∑ᵢ i * Cᵢ?
- The expression E5(n) is defined as Σ (nCk × k⁴) / Σ (nCk × k³), and it simplifies to n / 4. For n ≤ 109, E5(n) is less than 26. Therefore, the smallest value of n that satisfies the condition E5(n) ≥ 26 is one of the following:
- What is the coefficient of x¹¹ in the expansion of (1 + x²)⁴ (1 + x³)⁷ (1 + x)¹²?
- What is the coefficient of x⁵⁰ in the expansion of the sum S = sum(r=0 to 100) [ C(100,r) * (x-3)^(100-r) * 2^r ]?
- Evaluate the sum T = sum(r=0 to 20) r*(20-r)*[C(20,r)]².
⚔️ Practice JEE Advanced Maths free + battle 1v1 →