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ExamsJEE AdvancedMaths

The term independent of x in the expansion of (x² + x + 1 + 1/x)⁵ is equal to:

  1. 98
  2. 99
  3. 100
  4. 101

Correct answer: 101

Solution

Rewriting: (x²+x+1+1/x)⁵ = x^(-5)*(x³+x²+x+1)⁵. The term independent of x requires the x⁵ coefficient in (x³+x²+x+1)⁵.

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