StreakPeaked· Practice

ExamsJEE AdvancedMaths

Evaluate the definite integral: integral from -pi/2 to pi/2 of [x*sin(x) / (1 + e^x)] dx.

  1. pi²/4 - 2
  2. pi²/4 + 2
  3. 1
  4. pi² - e^(pi/2)

Correct answer: 1

Solution

By the symmetry property, f(x) + f(-x) = x*sin(x), so the integral equals (1/2)*integral_(-pi/2)^(pi/2) x*sin(x) dx = integral₀^(pi/2) x*sin(x) dx (since x*sin(x) is even). Integrating by parts gives [-x*cos(x) + sin(x)]₀^(pi/2) = 1.

Related JEE Advanced Maths questions

⚔️ Practice JEE Advanced Maths free + battle 1v1 →