Exams › JEE Advanced › Maths
The derivative of a function is given by f'(x) = (192x³)/(2 + sin⁴(π x)) for all x ∈ R, and it is known that f ((1)/(2)) = 0. If the integral ∫_(1/2)¹ f(x) dx is bounded such that m ≤ ∫_(1/2)¹ f(x) dx ≤ M, what are the possible values of m and M?
- m = 13, M = 24
- m = (1)/(4), M = (1)/(2)
- m = -11, M = 0
- m = 1, M = 12
Correct answer: m = 1, M = 12
Solution
The integral bounds for f(x) are determined by evaluating the given derivative and considering the constraints. The resulting range for the integral is 1 ≤ ∫ f(x) dx ≤ 12.
Related JEE Advanced Maths questions
⚔️ Practice JEE Advanced Maths free + battle 1v1 →