Exams › JEE Advanced › Maths
For x in (0, pi/2), evaluate: I = integral from 0 to sin²(x) of arcsin(sqrt(t)) dt + integral from 0 to cos²(x) of arccos(sqrt(t)) dt.
- pi/2
- 1
- pi/4
- None of these
Correct answer: pi/4
Solution
After substituting t = sin²(u) and t = cos²(u) in the two integrals respectively, they merge into the definite integral from 0 to pi/2 of u*sin(2u) du = pi/4.
Related JEE Advanced Maths questions
⚔️ Practice JEE Advanced Maths free + battle 1v1 →