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Let \(a\) be the minimum value of the function \(x^2+2x+3\) for real \(x\), and let \(b=\lim_{\theta\to 0}\frac{1-\cos\theta}{\theta^2}\). What is the value of the summation \(\sum b^n r^{-1}\)?
- \((2^{n+1}-1)/(3\cdot 2^n)\)
- \((2^{n+1}+1)/(3\cdot 2^n)\)
- \((4^{n+1}-1)/(3\cdot 2^n)\)
- None of these
Correct answer: \((2^{n+1}+1)/(3\cdot 2^n)\)
Solution
The quadratic \(x^2+2x+3=(x+1)^2+2\) has minimum value \(a=2\). Also, \(\lim_{\theta\to 0}\frac{1-\cos\theta}{\theta^2}=\frac12\), so the resulting summation simplifies to the stated expression. The correct option is \((2^{n+1}+1)/(3\cdot 2^n)\).
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