Evaluate f(x) = lim x→∞ (x²n − 1) / (x²n + 1). Which of the following is true?

Correct answer: f(x) equals 1 when |x| is greater than 1

Solution

The function f(x) equals 1 when |x| is greater than 1 because the limit of (x²n - 1) / (x²n + 1) as x approaches infinity is 1 for |x| > 1.

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