Exams › JEE Advanced › Chemistry
Correct answer: Ph2C+Me (diphenyl methyl-substituted cation)
Ph2C+Me has the positive carbon flanked by two phenyl rings; the charge is delocalised over both aromatic rings by resonance, giving very strong stabilisation (benzylic times two). The tert-butyl cation is only stabilised by hyperconjugation/inductive effects, the ethyl cation is a poorly stabilised primary cation, and the simple cyclohexadienyl cation is far less delocalised than a doubly benzylic system. Hence Ph2C+Me is most stable.