Exams › JEE Advanced › Chemistry
Arrange the following compounds in decreasing order of the oxidation number of nitrogen.
- HNO3, NO, NH4Cl, N2
- HNO3, NO, N2, NH4Cl
- HNO3, NH4Cl, NO, N2
- NO, HNO3, NH4Cl, N2
Correct answer: HNO3, NO, N2, NH4Cl
Solution
The oxidation states are HNO3 (+5) > NO (+2) > N2 (0) > NH4Cl (-3), giving the decreasing order HNO3, NO, N2, NH4Cl.
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