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The rate law for A + 2B -> P is d[P]/dt = k[A]²[B]. If A is taken in large excess, what is the observed order of the reaction?
- Zero
- 1
- 2
- 3
Correct answer: 1
Solution
If A is in large excess, [A]² is essentially constant and merges into k', giving rate = k'[B], a first order (pseudo-first order) reaction.
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