Exams › JEE Advanced › Chemistry

Given that C₁ represents the starting concentration of A, and C₁, C₂, and C₃ denote the concentrations of A, B, and C respectively at a specific time t, which equation can be used to calculate the values of k₁ and k₂?

1. C₂ = k₁C₀ [e⁻ᵏ¹ᵗ - e⁻ᵏ²ᵗ] / (k₂ - k₁)
2. C₂ = k₁C₁ [e⁻ᵏ¹ᵗ - e⁻ᵏ²ᵗ] / (k₂ - k₁)
3. C₂ = k₁C₀ [e⁻ᵏ¹ᵗ - e⁻ᵏ²ᵗ] / (k₁ - k₂)
4. None of the above

Correct answer: C₂ = k₁C₀ [e⁻ᵏ¹ᵗ - e⁻ᵏ²ᵗ] / (k₁ - k₂)

Solution

The equation C₂ = k₁C₀ [e⁻ᵏ¹ᵗ - e⁻ᵏ²ᵗ] / (k₁ - k₂) is used to calculate the values of k₁ and k₂ because it accurately represents the concentration of the intermediate species B at time t, taking into account the rates of formation and consumption of B.

Related JEE Advanced Chemistry questions

• The given equation implies that:
• In the reaction M → N, the rate at which M is consumed becomes 8 times faster when the concentration of M is doubled. What is the reaction order with respect to M?
• For the reaction A(g) + B(g) ⇌ AB(g), the activation energy for the reverse reaction is greater than that for the forward reaction by 2RT (in J mol⁻¹). If the forward reaction's pre-exponential factor is four times that of the backward reaction, what is the magnitude of ΔG⁰ (in J mol⁻¹) at 300 K?
• A gaseous compound X decomposes into gaseous products Y and Z according to first-order kinetics (X -> Y + Z). Initially only X is present. Ten minutes after the reaction begins, the partial pressure of X is 200 mmHg and the total pressure of the mixture is 300 mmHg. What is the rate constant for this reaction?
• A catalyst is added to a first-order reaction at 500 K, causing its rate to become 2.718 times the original rate. The activation energy with the catalyst present is 4.15 kJ/mol. What was the activation energy before the catalyst was introduced? (Given: R = 8.3 J/K/mol, ln(2.718) = 1)
• For the first-order gas-phase reaction A(g) -> 2B(g) + C(g), the following pressure data is recorded: Time (min): 0 100 infinity Total pressure (mmHg): 100 190 280 What is the half-life of the reaction?

⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →