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ExamsJEE AdvancedChemistry

For the reaction 2A + 3B -> 4C, the rate of reaction can be correctly written as:

  1. r = - 2 d(A)/dt = - 3 d(B)/dt = 4 d(C)/dt
  2. r = - 2 d(A)/dt = - 4 d(B)/dt = 3 d(C)/dt
  3. r = - 1/2 d(A)/dt = 1/3 d(B)/dt = 1/4 d(C)/dt
  4. r = - 1/2 d(A)/dt = - 1/3 d(B)/dt = 1/4 d(C)/dt

Correct answer: r = - 1/2 d(A)/dt = - 1/3 d(B)/dt = 1/4 d(C)/dt

Solution

Rate = -(1/2)d[A]/dt = -(1/3)d[B]/dt = +(1/4)d[C]/dt, with reactant terms negative and product term positive.

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