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A second-order reaction has a rate constant of 8 * 10⁻⁵ M⁻¹ min⁻¹. How long will it take for a 1 M solution to fall to 0.5 M?
- 8.665 * 10³ min
- 8 * 10⁻³ min
- 1.25 * 10⁴ min
- 4 * 10⁻⁵ min
Correct answer: 1.25 * 10⁴ min
Solution
Second-order half-life t = 1/(k[A]0) = 1/(8*10⁻⁵ * 1) = 1.25*10⁴ min.
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