Exams › JEE Advanced › Chemistry
When H2O2 reacts separately with (i) HIO4 and (ii) N2H4, identify the iodine-containing product and the nitrogen-containing product respectively.
- I−, NH3
- IO3−, NO3−
- IO3−, N2O
- I2, N2
Correct answer: IO3−, N2O
Solution
H2O2 reduces HIO4 (I = +7) to IO3- (I = +5), acting as a reducing agent. With N2H4, H2O2 acts as an oxidizing agent, partially oxidizing hydrazine to N2O (nitrous oxide).
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